45/y^2=5

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Solution for 45/y^2=5 equation: 


D( y )

y^2 = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

45/(y^2) = 5 // - 5

45/(y^2)-5 = 0

45*y^-2 = 5 // : 45

y^-2 = 1/9

-2 < 0

1/(y^2) = 1/9 // * y^2

1 = 1/9*y^2 // : 1/9

9 = y^2

y^2 = 9 // ^ 1/2

abs(y) = 3

y = 3 or y = -3

y in { 3, -3 }

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